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Let $\phi_{0}$ be the work function of the surface of the material
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$x_{\text {com }}=\frac{\sum_{i=1}^{n} m_{i} x_{i}}{M}, y_{\text {com }}=\frac{\sum_{i=1}^{n} m_{i} y_{i}}{M}$ and $z_{\text {com }}=\frac{\sum_{i=1}^{n} m_{i} z_{i}}{M}$
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The distance $x_{2}$ from point $b$ where the field is maximum, will be
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Ratio of magnitudes of charges $\left\frac{Q_{a}}{Q_{b}}\right$ will be equal to
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An object is displaced from position vector $\vec{r}_{1}=(2 \hat{i}+3 \hat{j}) \mathrm{m}$ to $\vec{r}_{2}=(4 \hat{i}+6 \hat{j}) \mathrm{m}$ under the action of a force $\vec{F}=\left(3 x^{2} \hat{i}+2 y \hat{j}\right) \mathbb{N}$. Find the work done by this force.
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Find The Correct option
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